18/1-3^2x+1=3^2-x

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Solution for 18/1-3^2x+1=3^2-x equation: 



18/1-3^2x+1=3^2-x

We move all terms to the left:

18/1-3^2x+1-(3^2-x)=0

We add all the numbers together, and all the variables

-3^2x-(3^2-x)=0

We get rid of parentheses

-3^2x+x-3^2=0

We add all the numbers together, and all the variables

x-3^2x-9=0

We move all terms containing x to the left, all other terms to the right

x-3^2x=9

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